Uses of Class
com.logicaldoc.audit.Subscription

Packages that use Subscription

Package	Description
com.logicaldoc.audit
com.logicaldoc.audit.webservice.model

Uses of Subscription in com.logicaldoc.audit

Methods in com.logicaldoc.audit that return Subscription

Modifier and Type	Method	Description
Subscription	HibernateSubscriptionDAO.findByAK(long userId, long objectId, String type)
Subscription	SubscriptionDAO.findByAK(long userId, long objectId, String type)	Retrieves all the subscriptions with the given alternate key.
Subscription	HibernateSubscriptionDAO.findByName(String name)
Subscription	SubscriptionDAO.findByName(String name)	Retrieves the subscription by the given name

Methods in com.logicaldoc.audit that return types with arguments of type Subscription

Modifier and Type	Method	Description
List<Subscription>	HibernateSubscriptionDAO.find(Long objectId, String type, String event, Long userId, Integer folderOption, Integer max)
List<Subscription>	SubscriptionDAO.find(Long objectId, String type, String event, Long userId, Integer folderOption, Integer max)	Retrieves all the subscriptions matching a set of criteria.
List<Subscription>	HibernateSubscriptionDAO.findByObjectIdAndType(long objectId, String type, String event, Integer folderOption)
List<Subscription>	SubscriptionDAO.findByObjectIdAndType(long objectId, String type, String event, Integer folderOption)	Retrieves all the subscriptions with the given object id and the given type
List<Subscription>	HibernateSubscriptionDAO.findByType(String type)
List<Subscription>	SubscriptionDAO.findByType(String type)	Retrieves all the subscriptions with the given type
List<Subscription>	HibernateSubscriptionDAO.findByUserId(long userId)
List<Subscription>	SubscriptionDAO.findByUserId(long userId)	This method selects all subscriptions of a given user

Uses of Subscription in com.logicaldoc.audit.webservice.model

Methods in com.logicaldoc.audit.webservice.model with parameters of type Subscription

Modifier and Type	Method	Description
static WSSubscription	WSSubscription.fromSubscription(Subscription s)